Question

$$\frac{\frac{3}{4}\cdot(\vec{\beta})}{-\frac{4}{16}}$$

Answer

$$34*e^2*v*c*b*t*a-416$$

Solution


Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[34v{e}^{2}cbta-416\]
Regroup terms.
\[34{e}^{2}vcbta-416\]