How to solve (3/5 + 35/50)/2

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (3/5 + 35/50)/2 | Equatix

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$$\frac{\frac{3}{5}+\frac{35}{50}}{2}$$

$\frac{13}{20}=0.65$

Reduce the fraction $\frac{35}{50}$ to lowest terms by extracting and canceling out $5$.

$$\frac{\frac{3}{5}+\frac{7}{10}}{2}$$

Least common multiple of $5$ and $10$ is $10$. Convert $\frac{3}{5}$ and $\frac{7}{10}$ to fractions with denominator $10$.

$$\frac{\frac{6}{10}+\frac{7}{10}}{2}$$

Since $\frac{6}{10}$ and $\frac{7}{10}$ have the same denominator, add them by adding their numerators.

$$\frac{\frac{6+7}{10}}{2}$$

Add $6$ and $7$ to get $13$.

$$\frac{\frac{13}{10}}{2}$$

Express $\frac{\frac{13}{10}}{2}$ as a single fraction.

$$\frac{13}{10\times 2}$$

Multiply $10$ and $2$ to get $20$.

$$\frac{13}{20}$$

$\frac{13}{2 ^ {2} \cdot 5} = 0.65$