Question

$$\frac{ \frac{ -2b+a-b }{ { b }^{ 2 } } }{ \frac{ { a }^{ 2 } b-a { b }^{ 2 } }{ (a { b }^{ 2 } )( { a }^{ 2 } b) } }$$

Answer

$$(a^2*(-3*b+a))/(a-b)$$

Solution


Collect like terms.
\[\frac{\frac{(-2b-b)+a}{{b}^{2}}}{\frac{{a}^{2}b-a{b}^{2}}{(a{b}^{2})({a}^{2}b)}}\]
Simplify  \((-2b-b)+a\)  to  \(-3b+a\).
\[\frac{\frac{-3b+a}{{b}^{2}}}{\frac{{a}^{2}b-a{b}^{2}}{a{b}^{2}{a}^{2}b}}\]
Factor out the common term \(ab\).
\[\frac{\frac{-3b+a}{{b}^{2}}}{\frac{ab(a-b)}{a{b}^{2}{a}^{2}b}}\]
Regroup terms.
\[\frac{\frac{-3b+a}{{b}^{2}}}{\frac{ab(a-b)}{a{a}^{2}{b}^{2}b}}\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[\frac{\frac{-3b+a}{{b}^{2}}}{\frac{ab(a-b)}{{a}^{1+2}{b}^{2+1}}}\]
Simplify  \(1+2\)  to  \(3\).
\[\frac{\frac{-3b+a}{{b}^{2}}}{\frac{ab(a-b)}{{a}^{3}{b}^{2+1}}}\]
Simplify  \(2+1\)  to  \(3\).
\[\frac{\frac{-3b+a}{{b}^{2}}}{\frac{ab(a-b)}{{a}^{3}{b}^{3}}}\]
Simplify  \(\frac{ab(a-b)}{{a}^{3}{b}^{3}}\)  to  \(\frac{a-b}{{a}^{2}{b}^{2}}\).
\[\frac{\frac{-3b+a}{{b}^{2}}}{\frac{a-b}{{a}^{2}{b}^{2}}}\]
Invert and multiply.
\[\frac{-3b+a}{{b}^{2}}\times \frac{{a}^{2}{b}^{2}}{a-b}\]
Cancel \({b}^{2}\).
\[(-3b+a)\times \frac{{a}^{2}}{a-b}\]
Use this rule: \(a \times \frac{b}{c}=\frac{ab}{c}\).
\[\frac{(-3b+a){a}^{2}}{a-b}\]
Regroup terms.
\[\frac{{a}^{2}(-3b+a)}{a-b}\]