Solve (F - 32)/180 = (40 + 0)/100 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$\frac{F-32}{180}=\frac{40-0}{100}$$

Solve for F

$F=104$

Steps for Solving Linear Equation

Multiply both sides of the equation by $900$, the least common multiple of $180,100$.

$$5\left(F-32\right)=9\left(40-0\right)$$

Use the distributive property to multiply $5$ by $F-32$.

$$5F-160=9\left(40-0\right)$$

Subtract $0$ from $40$ to get $40$.

$$5F-160=9\times 40$$

Multiply $9$ and $40$ to get $360$.

$$5F-160=360$$

Add $160$ to both sides.

$$5F=360+160$$

Add $360$ and $160$ to get $520$.

$$5F=520$$

Divide both sides by $5$.

$$F=\frac{520}{5}$$

Divide $520$ by $5$ to get $104$.

$$F=104$$