Example

3(r+2s)=2t-4
a⋅(b-2)=3b
3(r+2s)=2t-4
a⋅(b-2)=3b

Question

$$\frac{ h _{ 6- } 2 h _{ 5 } -2 h _{ \left( \right) _{ 3 } } + { h }^{ 2 } }{ { h }^{ 2 } -h }$$

Answer

$$(2*h_6-*h_5-2*h__3+h^2)/(h*(h-1))$$

Solution


Simplify  \(h_(6-)\times 2\)  to  \(2h_(6-)\).
\[\frac{2h_(6-)h_5-2h__3+{h}^{2}}{{h}^{2}-h}\]
Simplify  \(2h_(6-)\)  to  \(2h_6-\).
\[\frac{2h_6-h_5-2h__3+{h}^{2}}{{h}^{2}-h}\]
Factor out the common term \(h\).
\[\frac{2h_6-h_5-2h__3+{h}^{2}}{h(h-1)}\]
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