$$\frac{m-n}{4}+\frac{m-n}{7}$$
$\frac{11\left(m-n\right)}{28}$
$$\frac{11}{28}\left(m-n\right)$$
$$\frac{11}{28}m+\frac{11}{28}\left(-1\right)n$$
$$\frac{11}{28}m-\frac{11}{28}n$$
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$\frac{11m-11n}{28}$