Question

$$\frac{-1}{3}\times(\frac{1}{2}+\frac{1}{4})=(\frac{-1}{3}\times\frac{1}{2})+(\frac{-1}{3}\times\frac{1}{4})\vec{\Psi}$$

Answer

v=1/(e*cPs*IM)

Solution


Remove parentheses.
\[-13(12+14)=-13\times 12+(-13\times 14)vecPs\imath \]
Simplify  \(12+14\)  to  \(26\).
\[-13\times 26=-13\times 12+(-13\times 14)vecPs\imath \]
Simplify  \(-13\times 14\)  to  \(-182\).
\[-13\times 26=-13\times 12-182vecPs\imath \]
Simplify  \(-13\times 26\)  to  \(-338\).
\[-338=-13\times 12-182vecPs\imath \]
Simplify  \(13\times 12\)  to  \(156\).
\[-338=-156-182vecPs\imath \]
Regroup terms.
\[-338=-156-182ecPs\imath v\]
Add \(156\) to both sides.
\[-338+156=-182ecPs\imath v\]
Simplify  \(-338+156\)  to  \(-182\).
\[-182=-182ecPs\imath v\]
Divide both sides by \(-182\).
\[1=ecPs\imath v\]
Divide both sides by \(e\).
\[\frac{1}{e}=cPs\imath v\]
Divide both sides by \(cPs\).
\[\frac{\frac{1}{e}}{cPs}=\imath v\]
Simplify  \(\frac{\frac{1}{e}}{cPs}\)  to  \(\frac{1}{ecPs}\).
\[\frac{1}{ecPs}=\imath v\]
Divide both sides by \(\imath \).
\[\frac{\frac{1}{ecPs}}{\imath }=v\]
Simplify  \(\frac{\frac{1}{ecPs}}{\imath }\)  to  \(\frac{1}{ecPs\imath }\).
\[\frac{1}{ecPs\imath }=v\]
Switch sides.
\[v=\frac{1}{ecPs\imath }\]