Question

$$\frac{-12\div(-3)\times4-(-20)}{-6\times6\div3+(-6)}; 2\div(-3)x+-(-20)$$

Answer

36/(-18);2/(-3)*x+20

Solution


Move the negative sign to the left.
\[\begin{aligned}&\frac{-(-\frac{12}{3})\times 4-(-20)}{-6\times \frac{6}{3}-6}\\&\frac{2}{-3}x-(-20)\end{aligned}\]
Simplify  \(\frac{12}{3}\)  to  \(4\).
\[\begin{aligned}&\frac{-(-4)\times 4-(-20)}{-6\times \frac{6}{3}-6}\\&\frac{2}{-3}x-(-20)\end{aligned}\]
Remove parentheses.
\[\begin{aligned}&\frac{4\times 4-(-20)}{-6\times \frac{6}{3}-6}\\&\frac{2}{-3}x-(-20)\end{aligned}\]
Simplify  \(4\times 4\)  to  \(16\).
\[\begin{aligned}&\frac{16-(-20)}{-6\times \frac{6}{3}-6}\\&\frac{2}{-3}x-(-20)\end{aligned}\]
Remove parentheses.
\[\begin{aligned}&\frac{16+20}{-6\times \frac{6}{3}-6}\\&\frac{2}{-3}x-(-20)\end{aligned}\]
Simplify  \(16+20\)  to  \(36\).
\[\begin{aligned}&\frac{36}{-6\times \frac{6}{3}-6}\\&\frac{2}{-3}x-(-20)\end{aligned}\]
Use this rule: \(a \times \frac{b}{c}=\frac{ab}{c}\).
\[\begin{aligned}&\frac{36}{-\frac{6\times 6}{3}-6}\\&\frac{2}{-3}x-(-20)\end{aligned}\]
Simplify  \(6\times 6\)  to  \(36\).
\[\begin{aligned}&\frac{36}{-\frac{36}{3}-6}\\&\frac{2}{-3}x-(-20)\end{aligned}\]
Simplify  \(\frac{36}{3}\)  to  \(12\).
\[\begin{aligned}&\frac{36}{-12-6}\\&\frac{2}{-3}x-(-20)\end{aligned}\]
Simplify  \(-12-6\)  to  \(-18\).
\[\begin{aligned}&\frac{36}{-18}\\&\frac{2}{-3}x-(-20)\end{aligned}\]
Remove parentheses.
\[\begin{aligned}&\frac{36}{-18}\\&\frac{2}{-3}x+20\end{aligned}\]