Question

$$\frac{ -15 { x }^{ 3 } +12 { x }^{ 7 } }{ 3x }$$

Answer

$$-x^2*(5-4*x^4)$$

Solution


Factor out the common term \(3{x}^{3}\).
\[\frac{-3{x}^{3}(5-4{x}^{4})}{3x}\]
Move the negative sign to the left.
\[-\frac{3{x}^{3}(5-4{x}^{4})}{3x}\]
Cancel \(3\).
\[-\frac{{x}^{3}(5-4{x}^{4})}{x}\]
Simplify  \(\frac{{x}^{3}(5-4{x}^{4})}{x}\)  to  \({x}^{2}(5-4{x}^{4})\).
\[-{x}^{2}(5-4{x}^{4})\]