$$\frac{-2}{2-6+1+1-(-1-3)}$$
$-1$
$$\frac{-2}{-4+1+1-\left(-1-3\right)}$$
$$\frac{-2}{-3+1-\left(-1-3\right)}$$
$$\frac{-2}{-2-\left(-1-3\right)}$$
$$\frac{-2}{-2-\left(-4\right)}$$
$$\frac{-2}{-2+4}$$
$$\frac{-2}{2}$$
$$-1$$
Show Solution
Hide Solution