Example

3(r+2s)=2t-4
a⋅(b-2)=3b
3(r+2s)=2t-4
a⋅(b-2)=3b

Question

$$\frac{-20(2p-3q)^{12}(4-3r)^{3}}{-4(2p-3q)^{9}(4-3r)}$$

Answer

$$5*(2*p-3*q)^3*(4-3*r)^2$$

Solution


Two negatives make a positive.
\[\frac{20{(2p-3q)}^{12}{(4-3r)}^{3}}{4{(2p-3q)}^{9}(4-3r)}\]
Take out the constants.
\[\frac{20}{4}\times \frac{{(2p-3q)}^{12}{(4-3r)}^{3}}{{(2p-3q)}^{9}(4-3r)}\]
Simplify  \(\frac{20}{4}\)  to  \(5\).
\[5\times \frac{{(2p-3q)}^{12}{(4-3r)}^{3}}{{(2p-3q)}^{9}(4-3r)}\]
Simplify.
\[5{(2p-3q)}^{3}{(4-3r)}^{2}\]
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