Solve ) - 3/10 + 12/- 10 + 14/10 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$\frac { - 3 } { 10 } + \frac { 12 } { - 10 } + \frac { 14 } { 10 }$$

Evaluate

$-\frac{1}{10}=-0.1$

Solution Steps

Fraction $\frac{-3}{10}$ can be rewritten as $-\frac{3}{10}$ by extracting the negative sign.

$$-\frac{3}{10}+\frac{12}{-10}+\frac{14}{10}$$

Reduce the fraction $\frac{12}{-10}$ to lowest terms by extracting and canceling out $2$.

$$-\frac{3}{10}-\frac{6}{5}+\frac{14}{10}$$

Least common multiple of $10$ and $5$ is $10$. Convert $-\frac{3}{10}$ and $\frac{6}{5}$ to fractions with denominator $10$.

$$-\frac{3}{10}-\frac{12}{10}+\frac{14}{10}$$

Since $-\frac{3}{10}$ and $\frac{12}{10}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{-3-12}{10}+\frac{14}{10}$$

Subtract $12$ from $-3$ to get $-15$.

$$\frac{-15}{10}+\frac{14}{10}$$

Reduce the fraction $\frac{-15}{10}$ to lowest terms by extracting and canceling out $5$.

$$-\frac{3}{2}+\frac{14}{10}$$

Reduce the fraction $\frac{14}{10}$ to lowest terms by extracting and canceling out $2$.

$$-\frac{3}{2}+\frac{7}{5}$$

Least common multiple of $2$ and $5$ is $10$. Convert $-\frac{3}{2}$ and $\frac{7}{5}$ to fractions with denominator $10$.

$$-\frac{15}{10}+\frac{14}{10}$$

Since $-\frac{15}{10}$ and $\frac{14}{10}$ have the same denominator, add them by adding their numerators.

$$\frac{-15+14}{10}$$

Add $-15$ and $14$ to get $-1$.

$$-\frac{1}{10}$$

Factor

$-\frac{1}{10} = -0.1$