$$\frac{ -3 }{ 5 } + \frac{ 4 }{ 9 } + \frac{ -3 }{ 15 } + \frac{ -7 }{ 12 }$$
$-\frac{169}{180}\approx -0.938888889$
$$-\frac{3}{5}+\frac{4}{9}+\frac{-3}{15}+\frac{-7}{12}$$
$$-\frac{27}{45}+\frac{20}{45}+\frac{-3}{15}+\frac{-7}{12}$$
$$\frac{-27+20}{45}+\frac{-3}{15}+\frac{-7}{12}$$
$$-\frac{7}{45}+\frac{-3}{15}+\frac{-7}{12}$$
$$-\frac{7}{45}-\frac{1}{5}+\frac{-7}{12}$$
$$-\frac{7}{45}-\frac{9}{45}+\frac{-7}{12}$$
$$\frac{-7-9}{45}+\frac{-7}{12}$$
$$-\frac{16}{45}+\frac{-7}{12}$$
$$-\frac{16}{45}-\frac{7}{12}$$
$$-\frac{64}{180}-\frac{105}{180}$$
$$\frac{-64-105}{180}$$
$$-\frac{169}{180}$$
Show Solution
Hide Solution
$-\frac{169}{180} = -0.9388888888888889$