Solve - 3/8 + 1/7 = 1/7 - 3/8 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$\frac{-3}{8}+\frac{1}{7}=\frac{1}{7}+\frac{-3}{8}$$

Verify

$\text{true}$

Solution Steps

Fraction $\frac{-3}{8}$ can be rewritten as $-\frac{3}{8}$ by extracting the negative sign.

$$-\frac{3}{8}+\frac{1}{7}=\frac{1}{7}+\frac{-3}{8}$$

Least common multiple of $8$ and $7$ is $56$. Convert $-\frac{3}{8}$ and $\frac{1}{7}$ to fractions with denominator $56$.

$$-\frac{21}{56}+\frac{8}{56}=\frac{1}{7}+\frac{-3}{8}$$

Since $-\frac{21}{56}$ and $\frac{8}{56}$ have the same denominator, add them by adding their numerators.

$$\frac{-21+8}{56}=\frac{1}{7}+\frac{-3}{8}$$

Add $-21$ and $8$ to get $-13$.

$$-\frac{13}{56}=\frac{1}{7}+\frac{-3}{8}$$

Fraction $\frac{-3}{8}$ can be rewritten as $-\frac{3}{8}$ by extracting the negative sign.

$$-\frac{13}{56}=\frac{1}{7}-\frac{3}{8}$$

Least common multiple of $7$ and $8$ is $56$. Convert $\frac{1}{7}$ and $\frac{3}{8}$ to fractions with denominator $56$.

$$-\frac{13}{56}=\frac{8}{56}-\frac{21}{56}$$

Since $\frac{8}{56}$ and $\frac{21}{56}$ have the same denominator, subtract them by subtracting their numerators.

$$-\frac{13}{56}=\frac{8-21}{56}$$

Subtract $21$ from $8$ to get $-13$.

$$-\frac{13}{56}=-\frac{13}{56}$$

Compare $-\frac{13}{56}$ and $-\frac{13}{56}$.

$$\text{true}$$