How to solve 8 計劃 6 4

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 8 計劃 6 4 | Equatix

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Question

$$\frac { - 4 } { 5 } - \frac { - 3 } { 4 } + \frac { 6 } { 8 }$$

Evaluate

$\frac{7}{10}=0.7$

Solution Steps

Fraction $\frac{-4}{5}$ can be rewritten as $-\frac{4}{5}$ by extracting the negative sign.

$$-\frac{4}{5}-\frac{-3}{4}+\frac{6}{8}$$

Fraction $\frac{-3}{4}$ can be rewritten as $-\frac{3}{4}$ by extracting the negative sign.

$$-\frac{4}{5}-\left(-\frac{3}{4}\right)+\frac{6}{8}$$

The opposite of $-\frac{3}{4}$ is $\frac{3}{4}$.

$$-\frac{4}{5}+\frac{3}{4}+\frac{6}{8}$$

Least common multiple of $5$ and $4$ is $20$. Convert $-\frac{4}{5}$ and $\frac{3}{4}$ to fractions with denominator $20$.

$$-\frac{16}{20}+\frac{15}{20}+\frac{6}{8}$$

Since $-\frac{16}{20}$ and $\frac{15}{20}$ have the same denominator, add them by adding their numerators.

$$\frac{-16+15}{20}+\frac{6}{8}$$

Add $-16$ and $15$ to get $-1$.

$$-\frac{1}{20}+\frac{6}{8}$$

Reduce the fraction $\frac{6}{8}$ to lowest terms by extracting and canceling out $2$.

$$-\frac{1}{20}+\frac{3}{4}$$

Least common multiple of $20$ and $4$ is $20$. Convert $-\frac{1}{20}$ and $\frac{3}{4}$ to fractions with denominator $20$.

$$-\frac{1}{20}+\frac{15}{20}$$

Since $-\frac{1}{20}$ and $\frac{15}{20}$ have the same denominator, add them by adding their numerators.

$$\frac{-1+15}{20}$$

Add $-1$ and $15$ to get $14$.

$$\frac{14}{20}$$

Reduce the fraction $\frac{14}{20}$ to lowest terms by extracting and canceling out $2$.

$$\frac{7}{10}$$

Show Solution

Factor

$\frac{7}{2 \cdot 5} = 0.7$