1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

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Question

$$\frac { - 4 } { 9 } - \frac { - 3 } { 4 } + \frac { 6 } { 8 }$$

Evaluate

$\frac{19}{18}\approx 1.055555556$

Solution Steps

Fraction $\frac{-4}{9}$ can be rewritten as $-\frac{4}{9}$ by extracting the negative sign.

$$-\frac{4}{9}-\frac{-3}{4}+\frac{6}{8}$$

Fraction $\frac{-3}{4}$ can be rewritten as $-\frac{3}{4}$ by extracting the negative sign.

$$-\frac{4}{9}-\left(-\frac{3}{4}\right)+\frac{6}{8}$$

The opposite of $-\frac{3}{4}$ is $\frac{3}{4}$.

$$-\frac{4}{9}+\frac{3}{4}+\frac{6}{8}$$

Least common multiple of $9$ and $4$ is $36$. Convert $-\frac{4}{9}$ and $\frac{3}{4}$ to fractions with denominator $36$.

$$-\frac{16}{36}+\frac{27}{36}+\frac{6}{8}$$

Since $-\frac{16}{36}$ and $\frac{27}{36}$ have the same denominator, add them by adding their numerators.

$$\frac{-16+27}{36}+\frac{6}{8}$$

Add $-16$ and $27$ to get $11$.

$$\frac{11}{36}+\frac{6}{8}$$

Reduce the fraction $\frac{6}{8}$ to lowest terms by extracting and canceling out $2$.

$$\frac{11}{36}+\frac{3}{4}$$

Least common multiple of $36$ and $4$ is $36$. Convert $\frac{11}{36}$ and $\frac{3}{4}$ to fractions with denominator $36$.

$$\frac{11}{36}+\frac{27}{36}$$

Since $\frac{11}{36}$ and $\frac{27}{36}$ have the same denominator, add them by adding their numerators.

$$\frac{11+27}{36}$$

Add $11$ and $27$ to get $38$.

$$\frac{38}{36}$$

Reduce the fraction $\frac{38}{36}$ to lowest terms by extracting and canceling out $2$.

$$\frac{19}{18}$$

Show Solution

Factor

$\frac{19}{2 \cdot 3 ^ {2}} = 1\frac{1}{18} = 1.0555555555555556$