How to solve [- 5/16 + 7/12]

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve [- 5/16 + 7/12] | Equatix

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$$[\frac{-5}{16}+\frac{7}{12}]$$

$\frac{13}{48}\approx 0.270833333$

Fraction $\frac{-5}{16}$ can be rewritten as $-\frac{5}{16}$ by extracting the negative sign.

$$-\frac{5}{16}+\frac{7}{12}$$

Least common multiple of $16$ and $12$ is $48$. Convert $-\frac{5}{16}$ and $\frac{7}{12}$ to fractions with denominator $48$.

$$-\frac{15}{48}+\frac{28}{48}$$

Since $-\frac{15}{48}$ and $\frac{28}{48}$ have the same denominator, add them by adding their numerators.

$$\frac{-15+28}{48}$$

Add $-15$ and $28$ to get $13$.

$$\frac{13}{48}$$

$\frac{13}{2 ^ {4} \cdot 3} = 0.2708333333333333$