How to solve - 5/31 - (- 8/13)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve - 5/31 - (- 8/13) | Equatix

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$$\frac{-5}{31}-(\frac{-8}{13})$$

$\frac{183}{403}\approx 0.454094293$

Fraction $\frac{-5}{31}$ can be rewritten as $-\frac{5}{31}$ by extracting the negative sign.

$$-\frac{5}{31}-\frac{-8}{13}$$

Fraction $\frac{-8}{13}$ can be rewritten as $-\frac{8}{13}$ by extracting the negative sign.

$$-\frac{5}{31}-\left(-\frac{8}{13}\right)$$

The opposite of $-\frac{8}{13}$ is $\frac{8}{13}$.

$$-\frac{5}{31}+\frac{8}{13}$$

Least common multiple of $31$ and $13$ is $403$. Convert $-\frac{5}{31}$ and $\frac{8}{13}$ to fractions with denominator $403$.

$$-\frac{65}{403}+\frac{248}{403}$$

Since $-\frac{65}{403}$ and $\frac{248}{403}$ have the same denominator, add them by adding their numerators.

$$\frac{-65+248}{403}$$

Add $-65$ and $248$ to get $183$.

$$\frac{183}{403}$$

$\frac{3 \cdot 61}{13 \cdot 31} = 0.45409429280397023$