Example

3(r+2s)=2t-4
a⋅(b-2)=3b
3(r+2s)=2t-4
a⋅(b-2)=3b

Question

$$\frac{ -5 }{ 6 \times -18 } > 0$$

Answer

[Infinite Solutions]

Solution


Simplify  \(6\times -18\)  to  \(-108\).
\[\frac{-5}{-108}>0\]
Two negatives make a positive.
\[\frac{5}{108}>0\]
Since \(\frac{5}{108}>0\) is always true, there are infinitely many solutions.
Infinitely Many Solutions
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