How to solve - 6/13 and - 8/39

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve - 6/13 and - 8/39 | Equatix

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$$\frac { - 6 } { 13 } \frac { - 8 } { 39 }$$

$\frac{16}{169}\approx 0.094674556$

Fraction $\frac{-6}{13}$ can be rewritten as $-\frac{6}{13}$ by extracting the negative sign.

$$-\frac{6}{13}\times \frac{-8}{39}$$

Fraction $\frac{-8}{39}$ can be rewritten as $-\frac{8}{39}$ by extracting the negative sign.

$$-\frac{6}{13}\left(-\frac{8}{39}\right)$$

Multiply $-\frac{6}{13}$ times $-\frac{8}{39}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{-6\left(-8\right)}{13\times 39}$$

Do the multiplications in the fraction $\frac{-6\left(-8\right)}{13\times 39}$.

$$\frac{48}{507}$$

Reduce the fraction $\frac{48}{507}$ to lowest terms by extracting and canceling out $3$.

$$\frac{16}{169}$$

$\frac{2 ^ {4}}{13 ^ {2}} = 0.09467455621301775$