How to solve - 6/13 - (47/15)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve - 6/13 - (47/15) | Equatix

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$$\frac{-6}{13}-(\frac{47}{15})$$

$-\frac{701}{195}\approx -3.594871795$

Fraction $\frac{-6}{13}$ can be rewritten as $-\frac{6}{13}$ by extracting the negative sign.

$$-\frac{6}{13}-\frac{47}{15}$$

Least common multiple of $13$ and $15$ is $195$. Convert $-\frac{6}{13}$ and $\frac{47}{15}$ to fractions with denominator $195$.

$$-\frac{90}{195}-\frac{611}{195}$$

Since $-\frac{90}{195}$ and $\frac{611}{195}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{-90-611}{195}$$

Subtract $611$ from $-90$ to get $-701$.

$$-\frac{701}{195}$$

$-\frac{701}{195} = -3\frac{116}{195} = -3.594871794871795$