How to solve 6 35 4 + 35

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 6 35 4 + 35 | Equatix

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Question

$$\frac { - 6 } { 35 } - \frac { 1 } { 4 } + \frac { 1 } { 35 }$$

Evaluate

$-\frac{11}{28}\approx -0.392857143$

Solution Steps

Fraction $\frac{-6}{35}$ can be rewritten as $-\frac{6}{35}$ by extracting the negative sign.

$$-\frac{6}{35}-\frac{1}{4}+\frac{1}{35}$$

Least common multiple of $35$ and $4$ is $140$. Convert $-\frac{6}{35}$ and $\frac{1}{4}$ to fractions with denominator $140$.

$$-\frac{24}{140}-\frac{35}{140}+\frac{1}{35}$$

Since $-\frac{24}{140}$ and $\frac{35}{140}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{-24-35}{140}+\frac{1}{35}$$

Subtract $35$ from $-24$ to get $-59$.

$$-\frac{59}{140}+\frac{1}{35}$$

Least common multiple of $140$ and $35$ is $140$. Convert $-\frac{59}{140}$ and $\frac{1}{35}$ to fractions with denominator $140$.

$$-\frac{59}{140}+\frac{4}{140}$$

Since $-\frac{59}{140}$ and $\frac{4}{140}$ have the same denominator, add them by adding their numerators.

$$\frac{-59+4}{140}$$

Add $-59$ and $4$ to get $-55$.

$$\frac{-55}{140}$$

Reduce the fraction $\frac{-55}{140}$ to lowest terms by extracting and canceling out $5$.

$$-\frac{11}{28}$$

Show Solution

Factor

$-\frac{11}{28} = -0.39285714285714285$