How to solve - 7/12 - 13/18

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve - 7/12 - 13/18 | Equatix

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$$\frac{-7}{12}+\frac{-13}{18}$$

$-\frac{47}{36}\approx -1.305555556$

Fraction $\frac{-7}{12}$ can be rewritten as $-\frac{7}{12}$ by extracting the negative sign.

$$-\frac{7}{12}+\frac{-13}{18}$$

Fraction $\frac{-13}{18}$ can be rewritten as $-\frac{13}{18}$ by extracting the negative sign.

$$-\frac{7}{12}-\frac{13}{18}$$

Least common multiple of $12$ and $18$ is $36$. Convert $-\frac{7}{12}$ and $\frac{13}{18}$ to fractions with denominator $36$.

$$-\frac{21}{36}-\frac{26}{36}$$

Since $-\frac{21}{36}$ and $\frac{26}{36}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{-21-26}{36}$$

Subtract $26$ from $-21$ to get $-47$.

$$-\frac{47}{36}$$

$-\frac{47}{36} = -1\frac{11}{36} = -1.3055555555555556$