$$\frac{-8+(-5)\times(-8)-(-6)}{-3+(-8)\div2\times4}$$
$-2$
$$\frac{-8+40-\left(-6\right)}{-3+\frac{-8}{2}\times 4}$$
$$\frac{32-\left(-6\right)}{-3+\frac{-8}{2}\times 4}$$
$$\frac{32+6}{-3+\frac{-8}{2}\times 4}$$
$$\frac{38}{-3+\frac{-8}{2}\times 4}$$
$$\frac{38}{-3-4\times 4}$$
$$\frac{38}{-3-16}$$
$$\frac{38}{-19}$$
$$-2$$
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