$$\frac{-\frac{7}{4}-2}{3}+1=\frac{\frac{7}{4}}{7}$$
$\text{false}$
$$7\left(-\frac{7}{4}-2\right)+21=3\times \frac{7}{4}$$
$$7\left(-\frac{7}{4}-\frac{8}{4}\right)+21=3\times \frac{7}{4}$$
$$7\times \frac{-7-8}{4}+21=3\times \frac{7}{4}$$
$$7\left(-\frac{15}{4}\right)+21=3\times \frac{7}{4}$$
$$\frac{7\left(-15\right)}{4}+21=3\times \frac{7}{4}$$
$$\frac{-105}{4}+21=3\times \frac{7}{4}$$
$$-\frac{105}{4}+21=3\times \frac{7}{4}$$
$$-\frac{105}{4}+\frac{84}{4}=3\times \frac{7}{4}$$
$$\frac{-105+84}{4}=3\times \frac{7}{4}$$
$$-\frac{21}{4}=3\times \frac{7}{4}$$
$$-\frac{21}{4}=\frac{3\times 7}{4}$$
$$-\frac{21}{4}=\frac{21}{4}$$
$$\text{false}$$
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