Question

$$\frac{p}{3}-\frac{3p}{4}+\frac{7p}{g}=12-$$

Answer

g=(12-)/(7*p)+9/7

Solution


Regroup terms.
\[3p-3p\times 4+7pg=12-\]
Simplify  \(3p\times 4\)  to  \(12p\).
\[3p-12p+7pg=12-\]
Simplify  \(3p-12p+7pg\)  to  \(-9p+7pg\).
\[-9p+7pg=12-\]
Factor out the common term \(p\).
\[-p(9-7g)=12-\]
Divide both sides by \(-p\).
\[9-7g=-\frac{12-}{p}\]
Subtract \(9\) from both sides.
\[-7g=-\frac{12-}{p}-9\]
Divide both sides by \(-7\).
\[g=-\frac{-\frac{12-}{p}-9}{7}\]
Simplify  \(\frac{-\frac{12-}{p}-9}{7}\)  to  \(-\frac{\frac{12-}{p}}{7}-\frac{9}{7}\).
\[g=-(-\frac{\frac{12-}{p}}{7}-\frac{9}{7})\]
Simplify  \(\frac{\frac{12-}{p}}{7}\)  to  \(\frac{12-}{7p}\).
\[g=-(-\frac{12-}{7p}-\frac{9}{7})\]
Remove parentheses.
\[g=\frac{12-}{7p}+\frac{9}{7}\]