Question

$$\frac{(0.00042\times10^{-9})(15,000)}{(5000\times10^{7})(0.0021\times10^{14})}$$

Answer

$$(6.3*10^-30)/10.5$$

Solution


Remove parentheses.
\[\frac{0.00042\times {10}^{-9}\times 15000}{5000\times {10}^{7}\times 0.0021\times {10}^{14}}\]
Simplify  \(0.00042\times {10}^{-9}\times 15000\)  to  \((6.3)\times {10}^{-9}\).
\[\frac{6.3\times {10}^{-9}}{5000\times {10}^{7}\times 0.0021\times {10}^{14}}\]
Simplify  \(5000\times {10}^{7}\times 0.0021\times {10}^{14}\)  to  \((10.5)\times {10}^{7}\times {10}^{14}\).
\[\frac{6.3\times {10}^{-9}}{10.5\times {10}^{7}\times {10}^{14}}\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[\frac{6.3\times {10}^{-9}}{10.5\times {10}^{21}}\]
Use Quotient Rule: \(\frac{{x}^{a}}{{x}^{b}}={x}^{a-b}\).
\[6.3\times {10}^{-9-21}\times {10.5}^{-1}\]
Simplify  \(-9-21\)  to  \(-30\).
\[6.3\times {10}^{-30}\times {10.5}^{-1}\]
Use Negative Power Rule: \({x}^{-a}=\frac{1}{{x}^{a}}\).
\[6.3\times {10}^{-30}\times \frac{1}{10.5}\]
Use this rule: \(\frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}\).
\[\frac{6.3\times {10}^{-30}\times 1}{10.5}\]
Simplify  \(6.3\times {10}^{-30}\times 1\)  to  \((6.3)\times {10}^{-30}\).
\[\frac{6.3\times {10}^{-30}}{10.5}\]