$$\frac{ (1) { 3 }^{ 2 } -(-3) }{ (1)+(-3) { 2 }^{ 2 } } \div \frac{ -3+2 }{ { 1 }^{ 2 } 3(-2) }$$
$-\frac{72}{11}\approx -6.545454545$
$$\frac{\left(1\times 3^{2}-\left(-3\right)\right)\times 1^{2}\times 3\left(-2\right)}{\left(1-3\times 2^{2}\right)\left(-3+2\right)}$$
$$\frac{\left(1\times 9-\left(-3\right)\right)\times 1^{2}\times 3\left(-2\right)}{\left(1-3\times 2^{2}\right)\left(-3+2\right)}$$
$$\frac{\left(9-\left(-3\right)\right)\times 1^{2}\times 3\left(-2\right)}{\left(1-3\times 2^{2}\right)\left(-3+2\right)}$$
$$\frac{\left(9+3\right)\times 1^{2}\times 3\left(-2\right)}{\left(1-3\times 2^{2}\right)\left(-3+2\right)}$$
$$\frac{12\times 1^{2}\times 3\left(-2\right)}{\left(1-3\times 2^{2}\right)\left(-3+2\right)}$$
$$\frac{12\times 1\times 3\left(-2\right)}{\left(1-3\times 2^{2}\right)\left(-3+2\right)}$$
$$\frac{12\times 3\left(-2\right)}{\left(1-3\times 2^{2}\right)\left(-3+2\right)}$$
$$\frac{36\left(-2\right)}{\left(1-3\times 2^{2}\right)\left(-3+2\right)}$$
$$\frac{-72}{\left(1-3\times 2^{2}\right)\left(-3+2\right)}$$
$$\frac{-72}{\left(1-3\times 4\right)\left(-3+2\right)}$$
$$\frac{-72}{\left(1-12\right)\left(-3+2\right)}$$
$$\frac{-72}{-11\left(-3+2\right)}$$
$$\frac{-72}{-11\left(-1\right)}$$
$$\frac{-72}{11}$$
$$-\frac{72}{11}$$
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$-\frac{72}{11} = -6\frac{6}{11} = -6.545454545454546$
