$$\frac{ (2 { i }^{ 4 } +2 { i }^{ 6 } ) }{ (6i-7 { i }^{ 3 } ) }$$
$0$
$$\frac{2\times 1+2i^{6}}{6i-7i^{3}}$$
$$\frac{2+2i^{6}}{6i-7i^{3}}$$
$$\frac{2+2\left(-1\right)}{6i-7i^{3}}$$
$$\frac{2-2}{6i-7i^{3}}$$
$$\frac{0}{6i-7i^{3}}$$
$$\frac{0}{6i-7\left(-i\right)}$$
$$\frac{0}{6i-\left(-7i\right)}$$
$$\frac{0}{6i+7i}$$
$$\frac{0}{13i}$$
$$0$$
Show Solution
Hide Solution
$$Re(\frac{2\times 1+2i^{6}}{6i-7i^{3}})$$
$$Re(\frac{2+2i^{6}}{6i-7i^{3}})$$
$$Re(\frac{2+2\left(-1\right)}{6i-7i^{3}})$$
$$Re(\frac{2-2}{6i-7i^{3}})$$
$$Re(\frac{0}{6i-7i^{3}})$$
$$Re(\frac{0}{6i-7\left(-i\right)})$$
$$Re(\frac{0}{6i-\left(-7i\right)})$$
$$Re(\frac{0}{6i+7i})$$
$$Re(\frac{0}{13i})$$
$$Re(0)$$