$$\frac{(2x+1)/x+Ax+3)}{(x+1)^{2}}; \frac{(3x-2)(x+1)(x-3)}{(x-2)^{2}}$$
$\frac{\left(x-3\right)\left(3x-2\right)\left(x+1\right)}{\left(x-2\right)^{2}}$
$\frac{3x^{3}-8x^{2}-5x+6}{\left(x-2\right)^{2}}$