Question

$$\frac{(3)^{5}\times(6^{-3})}{(9)^{2}\times(6)^{-2}}$$

Answer

1/2

Solution


Use Negative Power Rule: \({x}^{-a}=\frac{1}{{x}^{a}}\).
\[\frac{{3}^{5}\times \frac{1}{{6}^{3}}}{{9}^{2}\times {6}^{-2}}\]
Simplify  \({3}^{5}\)  to  \(243\).
\[\frac{243\times \frac{1}{{6}^{3}}}{{9}^{2}\times {6}^{-2}}\]
Simplify  \({6}^{3}\)  to  \(216\).
\[\frac{243\times \frac{1}{216}}{{9}^{2}\times {6}^{-2}}\]
Simplify  \(243\times \frac{1}{216}\)  to  \(\frac{243}{216}\).
\[\frac{\frac{243}{216}}{{9}^{2}\times {6}^{-2}}\]
Simplify  \(\frac{243}{216}\)  to  \(\frac{9}{8}\).
\[\frac{\frac{9}{8}}{{9}^{2}\times {6}^{-2}}\]
Simplify  \({9}^{2}\)  to  \(81\).
\[\frac{\frac{9}{8}}{81\times {6}^{-2}}\]
Use Negative Power Rule: \({x}^{-a}=\frac{1}{{x}^{a}}\).
\[\frac{\frac{9}{8}}{81\times \frac{1}{{6}^{2}}}\]
Simplify  \({6}^{2}\)  to  \(36\).
\[\frac{\frac{9}{8}}{81\times \frac{1}{36}}\]
Simplify  \(81\times \frac{1}{36}\)  to  \(\frac{81}{36}\).
\[\frac{\frac{9}{8}}{\frac{81}{36}}\]
Simplify  \(\frac{81}{36}\)  to  \(\frac{9}{4}\).
\[\frac{\frac{9}{8}}{\frac{9}{4}}\]
Invert and multiply.
\[\frac{9}{8}\times \frac{4}{9}\]
Cancel \(9\).
\[\frac{1}{8}\times 4\]
Simplify.
\[\frac{4}{8}\]
Simplify.
\[\frac{1}{2}\]

Decimal Form: 0.5