$$\frac{(3x-1)}{5}-\frac{(1+x)}{2}=3-\frac{(x-1)}{2}$$
$x=7$
$$2\left(3x-1\right)-5\left(1+x\right)=30-5\left(x-1\right)$$
$$6x-2-5\left(1+x\right)=30-5\left(x-1\right)$$
$$6x-2-5-5x=30-5\left(x-1\right)$$
$$6x-7-5x=30-5\left(x-1\right)$$
$$x-7=30-5\left(x-1\right)$$
$$x-7=30-5x+5$$
$$x-7=35-5x$$
$$x-7+5x=35$$
$$6x-7=35$$
$$6x=35+7$$
$$6x=42$$
$$x=\frac{42}{6}$$
$$x=7$$
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