$$\frac{(3x+1)}{2}+\frac{(2x+5)}{3}=26$$
$x=11$
$$3\left(3x+1\right)+2\left(2x+5\right)=156$$
$$9x+3+2\left(2x+5\right)=156$$
$$9x+3+4x+10=156$$
$$13x+3+10=156$$
$$13x+13=156$$
$$13x=156-13$$
$$13x=143$$
$$x=\frac{143}{13}$$
$$x=11$$
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