Question

$$\frac{(48)^{-8}\times(64)^{\frac{1}{2}}}{(24)^{-1}}\cdot i$$

Answer

$$(68.135167781654*IM)/10^13$$

Solution


Use Negative Power Rule: \({x}^{-a}=\frac{1}{{x}^{a}}\).
\[\frac{\frac{1}{{48}^{8}}\times {64}^{\frac{1}{2}}}{{24}^{-1}}\imath \]
Simplify  \({48}^{8}\)  to  \(2.817928\times {10}^{13}\).
\[\frac{\frac{1}{2.817928\times {10}^{13}}\times {64}^{\frac{1}{2}}}{{24}^{-1}}\imath \]
Convert \({64}^{\frac{1}{2}}\) to square root.
\[\frac{\frac{1}{2.817928\times {10}^{13}}\sqrt{64}}{{24}^{-1}}\imath \]
Since \(8\times 8=64\), the square root of \(64\) is \(8\).
\[\frac{\frac{1}{2.817928\times {10}^{13}}\times 8}{{24}^{-1}}\imath \]
Simplify  \(\frac{1}{2.817928\times {10}^{13}}\times 8\)  to  \(\frac{8}{2.817928\times {10}^{13}}\).
\[\frac{\frac{8}{2.817928\times {10}^{13}}}{{24}^{-1}}\imath \]
Use Negative Power Rule: \({x}^{-a}=\frac{1}{{x}^{a}}\).
\[\frac{\frac{8}{2.817928\times {10}^{13}}}{\frac{1}{24}}\imath \]
Invert and multiply.
\[\frac{8}{2.817928\times {10}^{13}}\times 24\imath \]
Use this rule: \(\frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}\).
\[\frac{8\times 24\imath }{2.817928\times {10}^{13}}\]
Simplify  \(8\times 24\imath \)  to  \(192\imath \).
\[\frac{192\imath }{2.817928\times {10}^{13}}\]
Simplify.
\[\frac{68.135168\imath }{{10}^{13}}\]