Question

$$\frac{(4x-1)(3)-(3x+1)(4)}{(4x-1)^{2}}$$

Answer

$$-7/(4*x-1)^2$$

Solution


Regroup terms.
\[\frac{3(4x-1)-(3x+1)\times 4}{{(4x-1)}^{2}}\]
Regroup terms.
\[\frac{3(4x-1)-4(3x+1)}{{(4x-1)}^{2}}\]
Expand.
\[\frac{12x-3-12x-4}{{(4x-1)}^{2}}\]
Collect like terms.
\[\frac{(12x-12x)+(-3-4)}{{(4x-1)}^{2}}\]
Simplify  \((12x-12x)+(-3-4)\)  to  \(-7\).
\[\frac{-7}{{(4x-1)}^{2}}\]
Move the negative sign to the left.
\[-\frac{7}{{(4x-1)}^{2}}\]