Question

$$\frac{ (6.67 \times 6 \times 2)( { 10 }^{ -11 } )( { 10 }^{ 54 } ) }{ (1.5 \times 1.5)( { 10 }^{ 22) } }$$

Answer

$$(80.04*10^21)/2.25$$

Solution


Simplify  \(6.67\times 6\)  to  \(40.02\).
\[\frac{(40.02\times 2)\times {10}^{-11}\times {10}^{54}}{(1.5\times 1.5)\times {10}^{22}}\]
Simplify  \(40.02\times 2\)  to  \(80.04\).
\[\frac{80.04\times {10}^{-11}\times {10}^{54}}{(1.5\times 1.5)\times {10}^{22}}\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[\frac{80.04\times {10}^{43}}{(1.5\times 1.5)\times {10}^{22}}\]
Simplify  \(1.5\times 1.5\)  to  \(2.25\).
\[\frac{80.04\times {10}^{43}}{2.25\times {10}^{22}}\]
Use Quotient Rule: \(\frac{{x}^{a}}{{x}^{b}}={x}^{a-b}\).
\[80.04\times {10}^{43-22}\times {2.25}^{-1}\]
Simplify  \(43-22\)  to  \(21\).
\[80.04\times {10}^{21}\times {2.25}^{-1}\]
Use Negative Power Rule: \({x}^{-a}=\frac{1}{{x}^{a}}\).
\[80.04\times {10}^{21}\times \frac{1}{2.25}\]
Use this rule: \(\frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}\).
\[\frac{80.04\times {10}^{21}\times 1}{2.25}\]
Simplify  \(80.04\times {10}^{21}\times 1\)  to  \((80.04)\times {10}^{21}\).
\[\frac{80.04\times {10}^{21}}{2.25}\]