$$\frac{(7)[17(2-y)-5(y+12)]}{1-7y}=8$$
$y = -\frac{95}{49} = -1\frac{46}{49} \approx -1.93877551$
$$7\left(17\left(2-y\right)-5\left(y+12\right)\right)=8\left(-7y+1\right)$$
$$7\left(34-17y-5\left(y+12\right)\right)=8\left(-7y+1\right)$$
$$7\left(34-17y-5y-60\right)=8\left(-7y+1\right)$$
$$7\left(34-22y-60\right)=8\left(-7y+1\right)$$
$$7\left(-26-22y\right)=8\left(-7y+1\right)$$
$$-182-154y=8\left(-7y+1\right)$$
$$-182-154y=-56y+8$$
$$-182-154y+56y=8$$
$$-182-98y=8$$
$$-98y=8+182$$
$$-98y=190$$
$$y=\frac{190}{-98}$$
$$y=-\frac{95}{49}$$
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