Question

$$\frac{(a^{2})^{x+y}_{x}(a^{2})^{y-2}\times(a^{2})^{y+z}}{(a^{x},a^{y},a^{2})^{4}}$$

Answer

$$a^(2*x)+y*x*a^(2*y)-2*a^(2*y)+z*a^(x,a^y,4*a^2)$$

Solution


Use Power Rule: \({({x}^{a})}^{b}={x}^{ab}\).
\[{a}^{2x}+yx{({a}^{2})}^{y}-2{({a}^{2})}^{y}+z{({a}^{x},{a}^{y},{a}^{2})}^{4}\]
Use Power Rule: \({({x}^{a})}^{b}={x}^{ab}\).
\[{a}^{2x}+yx{a}^{2y}-2{a}^{2y}+z{({a}^{x},{a}^{y},{a}^{2})}^{4}\]
Use Power Rule: \({({x}^{a})}^{b}={x}^{ab}\).
\[{a}^{2x}+yx{a}^{2y}-2{a}^{2y}+z{a}^{x,{a}^{y},{a}^{2}\times 4}\]
Regroup terms.
\[{a}^{2x}+yx{a}^{2y}-2{a}^{2y}+z{a}^{x,{a}^{y},4{a}^{2}}\]