Since the power of 25 is odd, the result will be negative.
\[\frac{-{4}^{25}{x}^{12}{y}^{5}}{{(-4)}^{4}{x}^{5}{y}^{3}}\]
Simplify \({4}^{25}\) to \(1.125900\times {10}^{15}\).
\[\frac{-1.125900\times {10}^{15}{x}^{12}{y}^{5}}{{(-4)}^{4}{x}^{5}{y}^{3}}\]
Since the power of 4 is even, the result will be positive.
\[\frac{-1.125900\times {10}^{15}{x}^{12}{y}^{5}}{{4}^{4}{x}^{5}{y}^{3}}\]
Simplify \({4}^{4}\) to \(256\).
\[\frac{-1.125900\times {10}^{15}{x}^{12}{y}^{5}}{256{x}^{5}{y}^{3}}\]
Move the negative sign to the left.
\[-\frac{1.125900\times {10}^{15}{x}^{12}{y}^{5}}{256{x}^{5}{y}^{3}}\]
Take out the constants.
\[-\frac{1.125900}{256}\times \frac{{10}^{15}{x}^{12}{y}^{5}}{{x}^{5}{y}^{3}}\]
Simplify \(\frac{1.125900}{256}\) to \(0.004398\).
\[-0.004398\times \frac{{10}^{15}{x}^{12}{y}^{5}}{{x}^{5}{y}^{3}}\]
Use Quotient Rule: \(\frac{{x}^{a}}{{x}^{b}}={x}^{a-b}\).
\[-0.004398\times {10}^{15}{x}^{12-5}{y}^{5-3}\]
Simplify \(12-5\) to \(7\).
\[-0.004398\times {10}^{15}{x}^{7}{y}^{5-3}\]
Simplify \(5-3\) to \(2\).
\[-0.004398\times {10}^{15}{x}^{7}{y}^{2}\]
-0.0043980465111039*10^15*x^7*y^2
