$$\frac{(-40)}{99}\div\frac{(-20)}{11}$$
$\frac{2}{9}\approx 0.222222222$
$$\frac{-40\times 11}{99\left(-20\right)}$$
$$\frac{-2}{-9}$$
$$\frac{2}{9}$$
Show Solution
Hide Solution
$\frac{2}{3 ^ {2}} = 0.2222222222222222$
