Question

$$\frac{(s-15)(s+1)}{(3+02)}; \frac{(5-1)}{(5+1)(s-1)}$$

Answer

((s-15)*(s+1))/5;4/(6*(s-1))

Solution


Simplify  \(3+2\)  to  \(5\).
\[\begin{aligned}&\frac{(s-15)(s+1)}{5}\\&\frac{5-1}{(5+1)(s-1)}\end{aligned}\]
Simplify  \(5-1\)  to  \(4\).
\[\begin{aligned}&\frac{(s-15)(s+1)}{5}\\&\frac{4}{(5+1)(s-1)}\end{aligned}\]
Simplify  \(5+1\)  to  \(6\).
\[\begin{aligned}&\frac{(s-15)(s+1)}{5}\\&\frac{4}{6(s-1)}\end{aligned}\]