Question

$$\frac{(x-2)}{4}-\frac{(y-3)^{2}}{9}=1$$

Answer

$$x=4*(1+(y-3)^2/9)+2$$

Solution


Add \(\frac{{(y-3)}^{2}}{9}\) to both sides.
\[\frac{x-2}{4}=1+\frac{{(y-3)}^{2}}{9}\]
Multiply both sides by \(4\).
\[x-2=(1+\frac{{(y-3)}^{2}}{9})\times 4\]
Regroup terms.
\[x-2=4(1+\frac{{(y-3)}^{2}}{9})\]
Add \(2\) to both sides.
\[x=4(1+\frac{{(y-3)}^{2}}{9})+2\]