$$\frac{(x-3)(3x-1)-(2x-6)(x+1)}{1-x^{2}}$$
$\frac{\left(x-3\right)^{2}}{1-x^{2}}$
$$\frac{3x^{2}-10x+3-\left(2x-6\right)\left(x+1\right)}{1-x^{2}}$$
$$\frac{3x^{2}-10x+3-\left(2x^{2}-4x-6\right)}{1-x^{2}}$$
$$\frac{3x^{2}-10x+3-2x^{2}+4x+6}{1-x^{2}}$$
$$\frac{x^{2}-10x+3+4x+6}{1-x^{2}}$$
$$\frac{x^{2}-6x+3+6}{1-x^{2}}$$
$$\frac{x^{2}-6x+9}{1-x^{2}}$$
Show Solution
Hide Solution
$\frac{x^{2}-6x+9}{1-x^{2}}$
