How to solve R/(z + 15) = 4/9

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve R/(z + 15) = 4/9 | Equatix

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Question

$$\frac{R}{z+15}=\frac{4}{9}$$

Solve for R

$R=\frac{4\left(z+15\right)}{9}$
$z\neq -15$

Steps for Solving Linear Equation

Multiply both sides of the equation by $9\left(z+15\right)$, the least common multiple of $z+15,9$.

$$9R=4\left(z+15\right)$$

Use the distributive property to multiply $4$ by $z+15$.

$$9R=4z+60$$

Divide both sides by $9$.

$$\frac{9R}{9}=\frac{4z+60}{9}$$

Dividing by $9$ undoes the multiplication by $9$.

$$R=\frac{4z+60}{9}$$

Divide $60+4z$ by $9$.

$$R=\frac{4z}{9}+\frac{20}{3}$$

Show Solution

Solve for z

$z=\frac{9R}{4}-15$
$R\neq 0$

Steps for Solving Linear Equation

Variable $z$ cannot be equal to $-15$ since division by zero is not defined. Multiply both sides of the equation by $9\left(z+15\right)$, the least common multiple of $z+15,9$.

$$9R=4\left(z+15\right)$$

Use the distributive property to multiply $4$ by $z+15$.

$$9R=4z+60$$

Swap sides so that all variable terms are on the left hand side.

$$4z+60=9R$$

Subtract $60$ from both sides.

$$4z=9R-60$$

Divide both sides by $4$.

$$\frac{4z}{4}=\frac{9R-60}{4}$$

Dividing by $4$ undoes the multiplication by $4$.

$$z=\frac{9R-60}{4}$$

Divide $9R-60$ by $4$.

$$z=\frac{9R}{4}-15$$

Variable $z$ cannot be equal to $-15$.

$$z=\frac{9R}{4}-15\text{, }z\neq -15$$

Show Solution

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Example

Question

Solve for R

Steps for Solving Linear Equation

Solve for z

Steps for Solving Linear Equation