Use this rule: \(a \times \frac{b}{c}=\frac{ab}{c}\).
\[\frac{gs}{3}-\frac{1}{2}=\frac{s}{6}-\frac{1}{3}\]
Add \(\frac{1}{2}\) to both sides.
\[\frac{gs}{3}=\frac{s}{6}-\frac{1}{3}+\frac{1}{2}\]
Simplify \(\frac{s}{6}-\frac{1}{3}+\frac{1}{2}\) to \(\frac{s}{6}+\frac{1}{6}\).
\[\frac{gs}{3}=\frac{s}{6}+\frac{1}{6}\]
Join the denominators.
\[\frac{gs}{3}=\frac{s+1}{6}\]
Multiply both sides by \(3\).
\[gs=\frac{s+1}{6}\times 3\]
Simplify \(\frac{s+1}{6}\times 3\) to \(\frac{s+1}{2}\).
\[gs=\frac{s+1}{2}\]
Divide both sides by \(s\).
\[g=\frac{\frac{s+1}{2}}{s}\]
Simplify \(\frac{\frac{s+1}{2}}{s}\) to \(\frac{s+1}{2s}\).
\[g=\frac{s+1}{2s}\]
g=(s+1)/(2*s)
