Example

3(r+2s)=2t-4
a⋅(b-2)=3b
3(r+2s)=2t-4
a⋅(b-2)=3b

Question

$$\frac { \sqrt { 0 , 2 } } { 3 } + \frac { \sqrt { 7 , 2 } } { 4 } - \frac { 3 \sqrt { 0 , 05 } } { 2 } = a \sqrt { 5 }$$

Answer

a=(8.sqrt(0,2)/3+sqrt(7,2)/4-(3*sqrt(0,5))/2)/sqrt(5)

Solution


Remove parentheses.
\[\frac{8.\sqrt{0,2}}{3}+\frac{\sqrt{7,2}}{4}-\frac{3\sqrt{0,5}}{2}=a\sqrt{5}\]
Regroup terms.
\[\frac{8.\sqrt{0,2}}{3}+\frac{\sqrt{7,2}}{4}-\frac{3\sqrt{0,5}}{2}=\sqrt{5}a\]
Divide both sides by \(\sqrt{5}\).
\[\frac{\frac{8.\sqrt{0,2}}{3}+\frac{\sqrt{7,2}}{4}-\frac{3\sqrt{0,5}}{2}}{\sqrt{5}}=a\]
Switch sides.
\[a=\frac{\frac{8.\sqrt{0,2}}{3}+\frac{\sqrt{7,2}}{4}-\frac{3\sqrt{0,5}}{2}}{\sqrt{5}}\]
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