How to solve 2 날 2 올 2

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2 날 2 올 2 | Equatix

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Question

$$\frac { \sqrt { 3 } } { 2 } \times \frac { \sqrt { 3 } } { 2 } + \frac { 1 } { 2 } \times \frac { 1 } { 2 }$$

Evaluate

$1$

Solution Steps

Multiply $\frac{\sqrt{3}}{2}$ and $\frac{\sqrt{3}}{2}$ to get $\left(\frac{\sqrt{3}}{2}\right)^{2}$.

$$\left(\frac{\sqrt{3}}{2}\right)^{2}+\frac{1}{2}\times \frac{1}{2}$$

To raise $\frac{\sqrt{3}}{2}$ to a power, raise both numerator and denominator to the power and then divide.

$$\frac{\left(\sqrt{3}\right)^{2}}{2^{2}}+\frac{1}{2}\times \frac{1}{2}$$

Multiply $\frac{1}{2}$ times $\frac{1}{2}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{\left(\sqrt{3}\right)^{2}}{2^{2}}+\frac{1\times 1}{2\times 2}$$

Do the multiplications in the fraction $\frac{1\times 1}{2\times 2}$.

$$\frac{\left(\sqrt{3}\right)^{2}}{2^{2}}+\frac{1}{4}$$

To add or subtract expressions, expand them to make their denominators the same. Expand $2^{2}$.

$$\frac{\left(\sqrt{3}\right)^{2}}{4}+\frac{1}{4}$$

Since $\frac{\left(\sqrt{3}\right)^{2}}{4}$ and $\frac{1}{4}$ have the same denominator, add them by adding their numerators.

$$\frac{\left(\sqrt{3}\right)^{2}+1}{4}$$

The square of $\sqrt{3}$ is $3$.

$$\frac{3}{2^{2}}+\frac{1}{4}$$

Calculate $2$ to the power of $2$ and get $4$.

$$\frac{3}{4}+\frac{1}{4}$$

Since $\frac{3}{4}$ and $\frac{1}{4}$ have the same denominator, add them by adding their numerators.

$$\frac{3+1}{4}$$

Add $3$ and $1$ to get $4$.

$$\frac{4}{4}$$

Divide $4$ by $4$ to get $1$.

$$1$$

Show Solution

Factor

$1$