$$\frac { \sqrt { 3 } - \sqrt { 2 } } { \sqrt { 3 } + \sqrt { 2 } }$$
$5-2\sqrt{6}\approx 0.101020514$
$$\frac{\left(\sqrt{3}-\sqrt{2}\right)\left(\sqrt{3}-\sqrt{2}\right)}{\left(\sqrt{3}+\sqrt{2}\right)\left(\sqrt{3}-\sqrt{2}\right)}$$
$$\frac{\left(\sqrt{3}-\sqrt{2}\right)\left(\sqrt{3}-\sqrt{2}\right)}{\left(\sqrt{3}\right)^{2}-\left(\sqrt{2}\right)^{2}}$$
$$\frac{\left(\sqrt{3}-\sqrt{2}\right)\left(\sqrt{3}-\sqrt{2}\right)}{3-2}$$
$$\frac{\left(\sqrt{3}-\sqrt{2}\right)\left(\sqrt{3}-\sqrt{2}\right)}{1}$$
$$\left(\sqrt{3}-\sqrt{2}\right)\left(\sqrt{3}-\sqrt{2}\right)$$
$$\left(\sqrt{3}-\sqrt{2}\right)^{2}$$
$$\left(\sqrt{3}\right)^{2}-2\sqrt{3}\sqrt{2}+\left(\sqrt{2}\right)^{2}$$
$$3-2\sqrt{3}\sqrt{2}+\left(\sqrt{2}\right)^{2}$$
$$3-2\sqrt{6}+\left(\sqrt{2}\right)^{2}$$
$$3-2\sqrt{6}+2$$
$$5-2\sqrt{6}$$
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