$$\frac{\sqrt{3+1}}{\sqrt{3-1}}$$
$\sqrt{2}\approx 1.414213562$
$$\frac{\sqrt{4}}{\sqrt{3-1}}$$
$$\frac{2}{\sqrt{3-1}}$$
$$\frac{2}{\sqrt{2}}$$
$$\frac{2\sqrt{2}}{\left(\sqrt{2}\right)^{2}}$$
$$\frac{2\sqrt{2}}{2}$$
$$\sqrt{2}$$
Show Solution
Hide Solution
