$$\frac{t-2}{4}-\frac{2t+3}{3}=\frac{2}{3}-t$$
$t = \frac{26}{7} = 3\frac{5}{7} \approx 3.714285714$
$$3\left(t-2\right)-4\left(2t+3\right)=8-12t$$
$$3t-6-4\left(2t+3\right)=8-12t$$
$$3t-6-8t-12=8-12t$$
$$-5t-6-12=8-12t$$
$$-5t-18=8-12t$$
$$-5t-18+12t=8$$
$$7t-18=8$$
$$7t=8+18$$
$$7t=26$$
$$t=\frac{26}{7}$$
Show Solution
Hide Solution
